(2n-3)^4/(3-2n)^3

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Solution for (2n-3)^4/(3-2n)^3 equation: 


D( n )

(3-(2*n))^3 = 0

(3-(2*n))^3 = 0

(3-(2*n))^3 = 0

(3-2*n)^3 = 0

3-2*n = 0 // - 3

-2*n = -3 // : -2

n = -3/(-2)

n = 3/2

n in (-oo:3/2) U (3/2:+oo)

((2*n-3)^4)/((3-(2*n))^3) = 0

((2*n-3)^4)/((3-2*n)^3) = 0

2*n-3 = 0 // + 3

2*n = 3 // : 2

n = 3/2

n in { 3/2} 

n belongs to the empty set

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